Question

If the product of zeros of the polynomial $2x^2-6x-(6-a)$ is $4$, then find a.

• A. $2$
• B. $10$
• C. $16$
• D. $14$

Answer 1

Answer: (D)

$14$

$\Rightarrow$ The given quadratic equation is $2x^2-6x-(6-a)$, comparing it with $A{x}^2+Bx+C=0$

$\Rightarrow$ We get, $A=2,B=-6,C=-(6-a)$

$\Rightarrow$ Product of the zeros $=4$

$\Rightarrow$ $\frac{C}{A}=4$

$\Rightarrow$ $\frac{-(6-a)}{2}=4$

$\Rightarrow$ $-6+a=8$

$\Rightarrow$ $a=8+6$

$\therefore$ $a=14$