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Question

If the pth term of an AP is q and the qth term is p, prove that its nth term is (p+q-n).

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Solution


pth term = q
a+(p1)d=q
qth term = p
a+(q1)d=p
Solving these equations, we get,
d=1
a=(p+q1)
Thus,
nth term = a+(n1)d=(p+q1)+(n1)×(1)=(p+qn)

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