If the Pythagorean triples of one member is $10$ , find the other two members.

24

and

25

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24

and

26

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22

and

25

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23

and

25

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Solution

The correct option is C $24$ and $26$
As we know $2 m,$ $m^{2} + 1, m^{2} - 1$ form a Pythagorean triplet for any number $m > 1$ .
Let us assume $2 m = 10$
$\Rightarrow m = 5$
Therefore, $m^{2} + 1$ $=$ $5^{2} + 1$
$\Rightarrow 25 + 1 = 26$
$m^{2} - 1$ = $5^{2} - 1$
and $\Rightarrow 25 - 1 = 24$
Hence, the other two members are $24$ and $26$ .

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