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Question

If the quadratic equation, ax2+2cx+b=0 & ax2+2bx5x+c=0(bc) hava a common root then find the value of a+4b+4c.

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Solution

Considering the equations to be:

ax2+2cx+b=0...(1)

ax2+2bx+c=0...(2)

(2)-(1) gives

2(bc)x+cb=0

2(bc)x=bc

2x=1

x=12

From (1)

ax2+2cx+b=0

a(12)2+2c12+b=0

a+4c+4b=0


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