Question

If the quadratic equation $(k+1)x^2-2(k+1)x+1=0$ have real and equal roots then, find the value of k

Answer 1

Given $(k+1)x^2-2(k+1)x+1=0$ have real and equal roots

$⟹$Discriminant $=0$

$⟹(-2(k+1){)}^2-4(k+1\left)\right(1)=0$

$⟹(k+1{)}^2=(k+1)$

$⟹k+1=0$ or $k+1=1$

$⟹k=-1$ or $0$