Take quadratic equation
f(x)=px2+qx+r
If p>0, then,
px2+qx+r>0
It is only possible when D<0
⇒b2−4qr<0
If p<0, then
px2+qx+r<0
so, D<0
q2−4pr<0
So, relation between p,q and r is q2−4pr<0
If 2√3 is the root of quadratic equation px2+qx+r=0 for (p,q,r) belongs to R , then find value of (p+q+r)