Question

If the quadratic expression x - (a-1) x+(a+1) one to be a perfect square then a=?.

Answer 1

$x^2-(a-1)x+(a+1)=0$

perfect square $x=0$

$(a-1{)}^2-4(a+1)=0$

$a^2-2a+1-4a-4=0$

$a^2-6a-3=0$

$a$ is imaginary

Question is wrong.