Question

If the quantum numbers for the $5^{th}$ electron in carbon atom are $2,1,-1$, $+\frac{1}{2}$, then for the $6^{th}$ electron, these values would be:

• A. $1,1,0,-\frac{1}{2}$
• B. $2,0,1,+\frac{1}{2}$
• C. $2,1,1,-\frac{1}{2}$
• D. $2,1,0,+\frac{1}{2}$

Answer 1

The correct option is D $2,1,0,+\frac{1}{2}$

5th electron is present in $2p_x$ so the n,l,m and s values are $2,-1,1,+\frac{1}{2}$

6th electron is present in $2p_y$ so the n,l,m and s values are $2,1,0,+\frac{1}{2}$

Hence option D is correct.