If the quotient on dividing x3–3x2+6 by (x–1) is x2+ax+b, find a, b and also the remainder.
Consider p(x) = x3 – 3x2 + 6. The zero of the divisor is 1.
p(x) = (x – 1) (x2−2x−2)
The values of a = -2 and b = -2
The remainder is 4.