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Question

If the (r+1)th term in the expansion of (3ab+b3a)21 has the same power of a and b, then value of r is


A

9

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B

10

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C

8

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D

6

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Solution

The correct option is A

9


We have Tr+1 = 21Cr(3ab)21r(b3a)r

= 21Cra7(r2)b23r(72)

Since the powers of a and b are the same,

therefore

7 - r2 = 23r - 72 ⇒ r = 9


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