If the (r+1)th term in the expansion of (3√a√b+√b3√a)21 has the same power of a and b, then value of r is
9
We have Tr+1 = 21Cr(3√a√b)21−r(√b3√a)r
= 21Cra7−(r2)b23r−(72)
Since the powers of a and b are the same,
therefore
7 - r2 = 23r - 72 ⇒ r = 9