If the r.m.s. value of A.C. is $l_{r m s}$ then peak value is -

\sqrt{2} l_{r m s}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

l_{r m s} / \sqrt{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 \sqrt{2} l_{r m s}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 l_{r m s}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\sqrt{2} l_{r m s}$
$I_{p e a k} = \sqrt{2} I_{r m s}$
Hence,
option $(A)$ is correct answer.

Suggest Corrections

Similar questions

By how much does $\sqrt{12} + \sqrt{18} e x c e e d \sqrt{3} + \sqrt{2} ?$

6 sin 314 t

I = 5 sin 314 t

50

10

Join BYJU'S Learning Program