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Question

If the rth term is middle term in the expansion of (x212x)20 then find the (r+3)th term.

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Solution

Tr=T11
Thus, (r+3)th term is the 14th term of the given expansion
T14=20C13(x2)2013(12x)13=20C13.x.213
=20C13x.213[20C13=20C7]

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