If the rth term is middle term in the expansion of x2-12x20 then find the r-3th term-

∴ T _ r = T _ 11 Thus, (r+3) th term is the 14th term of the given expansion T _ 14 = _ #160; ^ 20 C _ 13 ( x ^ 2 ) #160; ^ 20 13 ( 1 2x ...

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Sum of n Terms

If the rth ...

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If the $r^{t h}$ term is middle term in the expansion of ${(x^{2} - \frac{1}{2 x})}^{20}$ then find the $(r + 3)^{t h}$ term.

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If rth term is the middle term in the expansion of ${(x^{2} - \frac{1}{2 x})}^{20}$ , then $(r + 3)^{t h}$ term is

r

{(x^{2} - \frac{1}{2 x})}^{20}

(r + 3)

{(x^{2} - \frac{1}{2 x})}^{20}

{(r + 3)}^{t h}

{}^{20}C_{14} (\frac{x}{2^{14}})

{}^{20}C_{12} x^{2} 2^{- 12}

- {}^{20}C_{7} x, 2^{- 13}

(2 r + 3)^{t h}

(r - 1)^{t h}

{(1 + x)}^{18}

r

{(x^{2} + \frac{1}{x})}^{n} i s 924 x^{6},

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