If the radii of the circular ends of a conical water glass are 25 and 12 cm whose height is 45 cm. Find the capacity of the water glass? (Use $π$ = 3.14)

50,349.9

c m^{3}

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51,349.9

c m^{3}

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52,349.9

c m^{3}

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53,349.9

c m^{3}

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Solution

The correct option is A 50,349.9 $c m^{3}$
Volume of a frustum cone = $\frac{π h}{3} (R^{2} + R r + r^{2})$
$= \frac{3.14 \times 45}{3} (25^{2} + 25 \times 12 + 12^{2})$
$= 47.1 (625 + 300 + 144)$
= $47.1 \times 1069$
= $50349.9 c m^{3}$

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If the radii of the circular ends of a conical water glass are 25 and 12 cm whose height is 45 cm. Find the capacity of the water glass? (Use π = 3.14)

The correct option is A 50,349.9 cm3Volume of a frustum cone = πh3(R2+Rr+r2)=3.14×453(252+25×12+122)=47.1(625+300+144)=47.1×1069= 50349.9cm3

If the radii of the circular ends of a conical water glass are 25 and 12 cm whose height is 45 cm. Find the capacity of the water glass? (Use $π$ = 3.14)

The correct option is A 50,349.9 $c m^{3}$
Volume of a frustum cone = $\frac{π h}{3} (R^{2} + R r + r^{2})$
$= \frac{3.14 \times 45}{3} (25^{2} + 25 \times 12 + 12^{2})$
$= 47.1 (625 + 300 + 144)$
= $47.1 \times 1069$
= $50349.9 c m^{3}$