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Question

If the radii of the ends of a bucket, 45 cm high, are 28 cm and 7 cm respectively, then the total surface area of the bucket is:

A
6074 cm2
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B
7074 cm2
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C
8074 cm2
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D
8274 cm2
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Solution

The correct option is C 8074 cm2

Total surface area of the bucket
=TSA=π×l×(r1+r2)+π×(r12+r22)

Where π=227,
l= Slant height of the bucket
=(h)2+(r1r2)2

r1=28cm and r2 = 7 cm

l= Slant height of the bucket
=(45)2+(21)2 cm=49.6 cm

Therefore,
TSA=[227×49.6×(28+7)+ 227×(282+72)]=8074 cm2


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