The correct option is D the value of the perimeter of a sector is always less than 2r+2πr
The formula for the perimeter of a sector is 2r+θ360∘×2πr, where θ is the angle subtended by the sector at the centre of the circle
The least possible value of θ is 0∘. But at θ=0∘, there will be no sector. So θ can attain any value greater than 0. At θ=0 the value of the perimeter of the sector is 2r. So, the value of the perimeter of a sector is always greater than 2r.
The maximum possible value of θ is 360∘. But at θ=360∘, it will be a complete circle. So θ can attain any value less than 360. At θ=360 the value of the perimeter of the sector is 2r+360∘360∘×2πr i.e. 2r+2πr So, the value of the perimeter of a sector is always less than 2r+2πr.
Options (a.) and (d.) are correct choices.