If the radius of a cylinder reduces by 50 $%$ , then volume of the cylinder reduces by

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Solution

Volume of new cylinder= $π$ $r^{2}$ h

= $π$ ${(\frac{R}{2})}^{2}$ h = $π$ $R^{2}$ $\frac{h}{4}$

= $\frac{1}{4}$ th of Volume of previous cylinder

= Reduction in volume by 75 $%$ .

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( Take $π = \frac{22}{7}$ )

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