Question

If the radius of a sphere is doubled then how many times of its volume is increased?

Answer 1

$V=\frac{4}{3}\pi r^3$

$\Rightarrow V^{\prime }=\frac{4}{3}\pi {\left(2r\right)}^3$

$=8.\frac{4}{3}\pi r^3$

$\therefore V^{\prime }=8V$

$=8$ times.

Hence, the answer is $8$ times.