If the radius of Br− ion is 0.182nm, how large can a cation be fit in its tetrahedral holes?
A
0.414pm
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B
0.0753pm
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C
0.091nm
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D
0.225pm
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Solution
The correct option is B0.0753pm For tetrahedral void, r+r−=0.225−0.414 r+=0.414×r− =0.414×0.182nm =0.0753nm ∴ The cation of radius 0.0753nm (maximum) can fit into each tetrahedral void.