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Question

If the radius of Br ion is 0.182 nm, how large can a cation be fit in its tetrahedral holes?

A
0.414 pm
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B
0.0753 pm
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C
0.091 nm
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D
0.225 pm
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Solution

The correct option is B 0.0753 pm
For tetrahedral void,
r+r=0.2250.414
r+=0.414×r
=0.414×0.182 nm
=0.0753 nm
The cation of radius 0.0753 nm (maximum) can fit into each tetrahedral void.

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