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Standard XII

Chemistry

Bohr's Model of a Hydrogen Atom

If the radius...

Question

If the radius of $B r^{-}$ ion is $0.182 n m$ , how large can a cation be fit in its tetrahedral holes?

0.414 p m

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0.0753 p m

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0.091 n m

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0.225 p m

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Solution

The correct option is B $0.0753 p m$
For tetrahedral void,
$\frac{r_{+}}{r_{-}} = 0.225 - 0.414$
$r_{+} = 0.414 \times r_{-}$
$= 0.414 \times 0.182 n m$
$= 0.0753 n m$
$∴$ The cation of radius $0.0753 n m$ (maximum) can fit into each tetrahedral void.

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If the radius of Br− ion is 0.182 nm, how large can a cation be fit in its tetrahedral holes?

The correct option is B 0.0753 pmFor tetrahedral void,r+r−=0.225−0.414r+=0.414×r−=0.414×0.182 nm=0.0753 nm∴ The cation of radius 0.0753 nm (maximum) can fit into each tetrahedral void.

If the radius of $B r^{-}$ ion is $0.182 n m$ , how large can a cation be fit in its tetrahedral holes?

The correct option is B $0.0753 p m$
For tetrahedral void,
$\frac{r_{+}}{r_{-}} = 0.225 - 0.414$
$r_{+} = 0.414 \times r_{-}$
$= 0.414 \times 0.182 n m$
$= 0.0753 n m$
$∴$ The cation of radius $0.0753 n m$ (maximum) can fit into each tetrahedral void.