1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# If the radius of earth shrinks by 0.2% without change in its mass, the time period of oscillation of a simple pendulum:

A
Increases by 0.2%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Decreases by 0.2%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Increases by 0.1%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Decreases by 0.1%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B Decreases by 0.2%Time period of oscillation of simple pendulum T=2π√lgThus percentage change in time period ΔTT×100=−12Δgg×100Also using g=GMR2We get percentage change in acceleration due to gravity Δgg×100=−2ΔRR×100⟹ ΔTT×100=ΔRR×100We get ΔTT×100=−0.2Thus time period of simple pendulum decreases by 0.2%.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Error and Uncertainty
PHYSICS
Watch in App
Join BYJU'S Learning Program