If the radius of first orbit of H - atom is $a_{0}$ , then de Broglie wavelength of electron in 4th orbit is ?

$2 π a_{0}$

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$16 a_{0}$

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$\frac{a_{0}}{4}$

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$8 π a_{0}$

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Solution

The correct option is D
$8 π a_{0}$

$r_{n} = a_{0} \times n^{2}, r_{4} = a_{0} \times 4^{2} = 16 a_{0} m v = 4. \frac{h}{2 π r_{4}} = \frac{4 h}{2 π \times 16 a_{0}} = \frac{h}{8 π a_{0}} λ = \frac{h}{m v} = 8 π a_{0}$

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Similar questions

H -

a_{0}

If the radius of first orbit of H - atom is $a_{0}$ , then de Broglie wavelength of electron in 4th orbit is ?

4^{t h}

r =

1^{s t}

x

4^{t h}

x

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