If the radius of $M g^{2 +}$ is $6.5 p m$ and $O_{2}^{-}$ is $14 p m$ , then calculate the coordination number of $M g^{2 +}$ in the crystal of $M g O$ .

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Solution

The correct option is A
6

Radius ratio = $\frac{r_{c a t i o n}}{r_{a n i o n}}$ = $\frac{r a d i u s o f M g^{2 +}}{r a d i u s o f O_{2}^{-}} = \frac{6.5}{14} = 0.48$

We can clearly see that 0.48 lies in the range of 0.414 – 0.732. So, we know that the coordination number is 6 directly.

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If the radius of $M g^{2 +}$ is $6.5 p m$ and $O_{2}^{-}$ is $14 p m$ , then calculate the coordination number of $M g^{2 +}$ in the crystal of $M g O$ .

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If the radius of Mg2+ is 6.5 pm and O−2 is 14 pm, then calculate the coordination number of Mg2+ in the crystal of MgO.

The correct option is A 6 Radius ratio = rcationranion= radius of Mg2+radius of O−2=6.514=0.48 We can clearly see that 0.48 lies in the range of 0.414 – 0.732. So, we know that the coordination number is 6 directly.

If the radius of $M g^{2 +}$ is $6.5 p m$ and $O_{2}^{-}$ is $14 p m$ , then calculate the coordination number of $M g^{2 +}$ in the crystal of $M g O$ .

The correct option is A
6

Radius ratio = $\frac{r_{c a t i o n}}{r_{a n i o n}}$ = $\frac{r a d i u s o f M g^{2 +}}{r a d i u s o f O_{2}^{-}} = \frac{6.5}{14} = 0.48$

We can clearly see that 0.48 lies in the range of 0.414 – 0.732. So, we know that the coordination number is 6 directly.