If the radius of $M g^{2 +}$ is $6.5 p m$ and $O_{2}^{-}$ is $14 p m$ , then calculate the coordination number of $M g^{2 +}$ in the crystal of $M g O$ .

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
6

Radius ratio = $\frac{r_{c a t i o n}}{r_{a n i o n}}$ = $\frac{r a d i u s o f M g^{2 +}}{r a d i u s o f O_{2}^{-}} = \frac{6.5}{14} = 0.48$

We can clearly see that 0.48 lies in the range of 0.414 – 0.732. So, we know that the coordination number is 6 directly.

Suggest Corrections

Similar questions

If the radius of $M g^{2 +}$ is $6.5 p m$ and $O_{2}^{-}$ is $14 p m$ , then calculate the coordination number of $M g^{2 +}$ in the crystal of $M g O$ .

Q. Ionic radii of

M g^{2 +}

and

O^{2 -}

ions are

66

pm and

140

pm respectively. The type of interstitial void and coordination number of

M g^{2 +}

ion are :

If the radius of Mg2+ ion, Cs+ ion, O2- ion, S2- ion and Cl- ion are 0.65 Å , 1.69 Å, 1.40 Å, 1.84 Å, and 1.81 Å respectively. Then the co-ordination numbers of the cations in the crystals of MgS, MgO and CsCl respectively are:

Q. If the radius of