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Question

If the radius of second stationary orbit (in Bohr's atom) is R. Then, the radius of third orbit will be:


A
R/3
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B
9R
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C
R/9
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D
2.25R
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Solution

The correct option is D 2.25R
$$r = 0.529 \times \cfrac{{{n^2}}}{z}$$

$$r \propto {n^2}$$

$$R \propto {(2)^2}$$                          $$.......(1)$$

$${R_1} \propto (3)^2$$                           $$.......(2)$$

Divide (1) by (2)

$$\frac{{{R_1}}}{R} = \cfrac{4}{9}$$

$${R_1} = \cfrac{{9R}}{4}$$

$$R_1= 2.25 R$$

Chemistry

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