If the radius of the circle with centre O is 13 cm and the length of the two chords AB and CD is 24 cm. Find the distance between the chords.

8 cm

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10 cm

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12 cm

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14 cm

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16 cm

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Solution

The correct option is B
10 cm

Let the perpendicular from the centre to AB meet at E. Perpendicular from the centre bisects the chord. Using Pythagoras theorem in $Δ$ AOB - x $^{2}$ + 12 $^{2}$ = 13 $^{2}$ $\Rightarrow$ x = 5 Distance = 10 cm

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If the radius of the circle with centre O is 13 cm and the length of the two chords AB and CD is 24 cm. Find the distance between the chords.

The correct option is B 10 cm Let the perpendicular from the centre to AB meet at E. Perpendicular from the centre bisects the chord. Using Pythagoras theorem in ΔAOB - x2 + 122 = 132 ⇒ x = 5 Distance = 10 cm

The correct option is B
10 cm

Let the perpendicular from the centre to AB meet at E. Perpendicular from the centre bisects the chord. Using Pythagoras theorem in $Δ$ AOB - x $^{2}$ + 12 $^{2}$ = 13 $^{2}$ $\Rightarrow$ x = 5 Distance = 10 cm