If the radius of the circle with centre O is 13 cm and the length of the two chords AB and CD is 24 cm. Find the distance between the chords.
10 cm
Let the perpendicular from the centre to AB meet at E. Perpendicular from the centre bisects the chord. Using Pythagoras theorem in ΔAOB - x2 + 122 = 132 ⇒ x = 5 Distance = 10 cm