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Question

If the radius of the circle with centre O is 13 cm and the length of the two chords AB and CD is 24 cm. Find the distance between the chords.


A

8 cm

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B

10 cm

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C

12 cm

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D

16 cm

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Solution

The correct option is B

10 cm


Let the perpendicular from the centre to AB meet at E. Perpendicular from the centre bisects the chord. Using Pythagoras theorem in ΔAOB - x2 + 122 = 132 x = 5 Distance = 10 cm


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