If the radius of the circle $x^{2} + y^{2}$ + 8x + 10y + k = 0 is 7, Then k =

-7

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-8

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Solution

The correct option is C
-8

$r a d i u s = 7 \Rightarrow \sqrt{16 + 25 - K} = 7 \Rightarrow 41 - K = 49 \Rightarrow K = - 8$

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