Question

If the radius of the circular field is equal to the side of a square field and if the difference between the area of the circular field and the area of the square field is $5145sq.m.$, then calculate the perimeter of the circular field?

Answer 1

Let the radius of the circular field be $r$ and the side of the square field be $a$

According to question $r=a$

Also According to question

$\pi r^2$ $-$ $a^2=5145$

$\Rightarrow r^2(\pi -1)=5145$

$\Rightarrow r^2=\frac{5145}{(\pi -1)}$

$\Rightarrow r^2=\frac{5145}{(\frac{22}{7}-1)}$

$\Rightarrow r^2=\frac{5145}{\frac{15}{7}}$

$\Rightarrow r^2=\frac{5145\times 7}{15}$

$\Rightarrow r^2=343\times 7$

Solving we get $r=a=49m$

So permimeter of circular field

$=2\pi r$

$=308$m