If the radius of the earth is reduced by 1% keeping the mass constant. The escape velocity will :
A
increase by 0.5%
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B
decrease by 0.5%
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C
decrease by 11%
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D
remain same
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Solution
The correct option is C decrease by 0.5% Escape speed is ve=√2GMR It is given that only radius is changing while mass is constant. Differentiating ve with respect to R gives ΔvΔR=−12√2GM×R−3/2=−12√2GMR×1R=−12vR; where Δ indicates change. ∴△vv×100=−12ΔRR×100=−12×(−1)=0.5; (−1 because it reduced )