If the radius of the hydrogen atom is 53 pm, the radius of the He $^{+}$ ion is closest to

108 pm

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81 pm

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27 pm

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13 pm

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Solution

The correct option is C
27 pm

$r_{n} = \frac{R_{H} n^{2}}{Z}$
$r_{H_{e +}} = \frac{53 n^{2}}{Z}$
$= \frac{53 \times 1^{2}}{2} = 27$ approx

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