Question

If the range of a gun which fires a shell with muzzle speed V is R , then the angle of elevation of the gun is

• A. $co{s}^{-1}\left(\frac{V^2}{Rg}\right)$
• B. $co{s}^{-1}\left(\frac{gR}{V^2}\right)$
• C. $\frac{1}{2}\left(\frac{V^2}{Rg}\right)$
• D. $\frac{1}{2}si{n}^{-1}\left(\frac{gR}{V^2}\right)$

Answer 1

The correct option is D

$\frac{1}{2}si{n}^{-1}\left(\frac{gR}{V^2}\right)$

$R=\frac{v^{2}sin2\theta }{g}\Rightarrow \theta =\frac{1}{2}si{n}^{-1}\left(\frac{gR}{v^2}\right)$