If the rate of reaction A→B doubles on increasing the concentration of A by 4 times, then the order of reaction is :
A
2
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B
1
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C
12
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D
4
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Solution
The correct option is C12 Let the rate of the reaction be r=K[A]n .........(1) When [A]→4[A], rate will be r→2r 2r=4n[A]n ..........(2) By comparing equations (2) and (1), 2=4n This is only possible when n=12.