Question

If opposite angles in a parallelogram are 110 degrees each, what are the other 2 angles?

• A. 70 Degrees Each
• B. 110 Degrees Each
• C. 220 Degrees Each
• D. 140 Degrees Each

Answer 1

The correct option is A

70 Degrees Each

Given that,

Opposite angles in a parallelogram are 110 degrees each.

Let the angles be $\angle ,\angle B,\angle C,\angle D$

Then, $\angle A+\angle B+\angle C+\angle D={360}^{\circ }$ [Sum of angles of quadrilateral is ${360}^{\circ }$]

$2\angle +2\angle B={360}^{\circ }$ [$\because$Opposite angles in a parallelogram are 110 degrees each]

$\Rightarrow {220}^{\circ }+2\angle B={360}^{\circ }$ [$\because$ Opposite angles in a parallelogram are 110 degrees each]

$\Rightarrow 2\angle B={360}^{\circ }-{220}^{\circ }$

$\Rightarrow 2\angle B={140}^{\circ }$

$\Rightarrow \angle B={70}^{\circ }$