If the ratio of radii of two cylinders is 2 : 1 and ratio of their heights is 3 : 4, find the ratio of curved surface areas of the cylinders.

4 : 5

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1 : 2

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3 : 5

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3 : 2

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Solution

The correct option is D 3 : 2
Given: Ratio of radii = 2 : 1, ratio of heights = 3 : 4

Let the radii of the cylinders are 2x and x.
Heights of the cylinders are 3y and 4y.

$\frac{C S A o f c y l i n d e r 1}{C S A o f c y l i n d e r 2}$ = $\frac{2 π r h}{2 π R H}$

$\frac{C S A o f c y l i n d e r 1}{C S A o f c y l i n d e r 2}$ = $\frac{r h}{R H}$

$\frac{C S A o f c y l i n d e r 1}{C S A o f c y l i n d e r 2}$ = $\frac{(2 x) (3 y)}{(x) (4 y)}$

$\frac{C S A o f c y l i n d e r 1}{C S A o f c y l i n d e r 2}$ = $\frac{3}{2}$

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