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Question

If the ratio of specific heat of a gas at constant pressure to that at constant volume is γ , the change in internal energy of the mass of gas, when the volume changes from V to 2V at constant pressure P is :

A
R(γ1)
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B
PV
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C
PV(γ1)
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D
γPV(γ1)
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Solution

The correct option is C PV(γ1)
Using first law we have ΔQ=ΔU+ΔW
For an isobaric process we have ΔW=PV
And ΔQ is given as nCpΔT=nγRγ1ΔT
Using Gas Law equation, we have PV=nRΔT
Thus, we get ΔQ=γγ1PV
Hence,
ΔU=γγ1PVPV=PVγ1

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