If the ratio of the altitude and area of a triangle is $3 : 12$ , then find the length of the base of triangle.

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Solution

As Area of traingle , $A = \frac{1}{2} \times b a s e (b) \times A t i a t u d e (h)$
Given , $\frac{h}{A} = \frac{3}{12} \Rightarrow \frac{h}{\frac{1}{2} \times b \times h} = \frac{1}{4} \Rightarrow \frac{2}{b} - \frac{1}{4} \Rightarrow b = 8$

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If the ratio of the altitude and area of a triangle is 3:12, then find the length of the base of triangle.

As Area of traingle , A=12×base(b)×Atiatude(h)Given ,hA=312⇒h12×b×h=14⇒2b−14⇒b=8

If the ratio of the altitude and area of a triangle is $3 : 12$ , then find the length of the base of triangle.

As Area of traingle , $A = \frac{1}{2} \times b a s e (b) \times A t i a t u d e (h)$
Given , $\frac{h}{A} = \frac{3}{12} \Rightarrow \frac{h}{\frac{1}{2} \times b \times h} = \frac{1}{4} \Rightarrow \frac{2}{b} - \frac{1}{4} \Rightarrow b = 8$