If the ratio of the concentration of electrons to that of holes in a semiconductor is 7-5 and the ratio of current is 7-4- then what is the ratio of their drift velocities-

The correct option is B 5/4 I_eI_h = n_eeAv_en_heAv_h⇒7/4 = 75×V_eV_h ⇒V_eV_h = 54 ...

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Byju's Answer

Standard XII

Physics

Mechanism of Formation of P-N Junction

If the ratio ...

Question

If the ratio of the concentration of electrons to that of holes in a semiconductor is $\frac{7}{5}$ and the ratio of current is $\frac{7}{4}$ , then what is the ratio of their drift velocities?

\frac{5}{8}

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\frac{4}{5}

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\frac{5}{4}

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\frac{4}{7}

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Solution

The correct option is B $\frac{5}{4}$
$\frac{I_{e}}{I_{h}} = \frac{n_{e} e A v_{e}}{n_{h} e A v_{h}} \Rightarrow \frac{7}{4} = \frac{7}{5} \times \frac{V_{e}}{V_{h}}$
$\Rightarrow \frac{V_{e}}{V_{h}} = \frac{5}{4}$

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Similar questions

If the ratio of concentration of electrons to that of holes in a semiconductors is $\frac{7}{5}$ and the ratio of currents is $\frac{7}{4}$ , what is the ratio of their drift velocities?

Q. If the ratio of the concentration of electrons to that of holes in a semiconductors is

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and the ratio of currents is

\frac{7}{4}

, then the ratio of drift velocities is

Q. If the ratio of the concentration of electrons to that of holes in a semiconductor is

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and the ratio of current is

\frac{7}{4},

then the ratio of their drift velocities is

\frac{N}{8} .

The value of

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(integer only)

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, the ratio of currents is

\frac{5}{4}

and the ratio of their drift velocities is

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, then the value of

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is .

Q. The ratio of electron and hole currents in a semiconductor is

7 / 4

and the ratio of drift velocities of electrons and holes is

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, then the ratio of concentrations of electrons and holes will be

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If the ratio of the concentration of electrons to that of holes in a semiconductor is 75 and the ratio of current is 74, then what is the ratio of their drift velocities?

The correct option is B 54IeIh=neeAvenheAvh⇒74=75×VeVh⇒VeVh=54

If the ratio of the concentration of electrons to that of holes in a semiconductor is $\frac{7}{5}$ and the ratio of current is $\frac{7}{4}$ , then what is the ratio of their drift velocities?

The correct option is B $\frac{5}{4}$
$\frac{I_{e}}{I_{h}} = \frac{n_{e} e A v_{e}}{n_{h} e A v_{h}} \Rightarrow \frac{7}{4} = \frac{7}{5} \times \frac{V_{e}}{V_{h}}$
$\Rightarrow \frac{V_{e}}{V_{h}} = \frac{5}{4}$