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Question

If the reading of the spring balance (massless) is $10 x$ (in Newton) then find $x$ . ( $g = 10 m / s^{2}$ )

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Solution

$b l o c k A, T = m (g + a) T = 40 (10 + a) \to (1) b l o c k B, T = m (g - a) T = 10 (10 - a) \to (2) (1) = (2) 40 (10 + a) = 10 (10 - a) \Rightarrow a = - 6 ㎨ T = 40 (10 - 6) = 40 \times 4 = 160 N ∴ R e a d i n g 10 x = 160 x = 16$

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