If the real valued function f(x)=ax−1xn(ax+1) is even, then n is equal to
A
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
14
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D3 f(x)=ax−1xn(ax+1) ⇒f(−x)=a−x−1(−x)n(a−x+1) =1−ax(−1)nxn(ax+1) Since, f(x) is even function. Therefore, f(x)=f(−x) ⇒ax−1xn(ax+1)=1−ax(−1)nxn(ax+1) ⇒(−1)n=(−1) It satisfies, if n is odd Hence, n=3