If the real-valued function f(x)=px+sinx is a bijective function, then the set of all possible values of pϵR is?
A
R−{0}
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B
R
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C
(0,∞)
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D
None of these
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Solution
The correct option is AR−{0} Given, the function f(x)=px+sinx is a bijective function. Which implies, there exists a function g(x) such that f(g(x))=g(f(x))=x for, xϵR.
This argument doesn't work if p=0 because it would involve division by zero.
Hence, the set of all possible values of pϵR is R−{0}.