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Question

If the real-valued function f(x)=px+sinx is a bijective function, then the set of all possible values of pϵR is?

A
R{0}
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B
R
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C
(0,)
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D
None of these
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Solution

The correct option is A R{0}
Given, the function f(x)=px + sinx is a bijective function. Which implies, there exists a function g(x) such that f(g(x))=g(f(x))=x for, xϵR.
This argument doesn't work if p=0 because it would involve division by zero.

Hence, the set of all possible values of pϵR is R{0}.

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