wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the rectangular hyperbola is x2−y2=64. Then, which of the following is not correct?

A
The length of latus rectum is 16
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
The eccentricity is 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
The asymptotes are parallel to each other
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
The directrices are x=±42
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D The asymptotes are parallel to each other
Given equation of rectangular hyperbola is x2y2=82
Here, a=8 and b=a
Length of latus rectum =2×b2a=2×(8)=16
and eccentricity =2
The asymptotes are perpendicular lines.
So, x±y=0
Now, directrices are
x=±82=±42
Hence, statement given in C is not correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Line and a Parabola
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon