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Standard X

Physics

Refraction

If the refrac...

Question

If the refractive index of second medium with the respect to first medium is $_{2} n_{1}$ and that of third medium with respect to second medium is $_{3} n_{2}$ , then $_{3} n_{1}$ will be?

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Solution

$_{2} n_{1} = \frac{n_{2}}{n_{1}}$ ...(1)

$_{3} n_{2} = \frac{n_{3}}{n_{2}}$ ...(2)

multiply (1) and (2)

$_{2} n_{1} \times_{3} n_{2} = \frac{n_{2}}{n_{1}} \times \frac{n_{3}}{n_{2}}$

$_{3} n_{1} = \frac{n_{3}}{n_{1}}$

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If the refractive index of second medium with the respect to first medium is 2n1 and that of third medium with respect to second medium is 3n2, then 3n1 will be?

2n1=n2n1 ...(1)3n2=n3n2 ...(2)multiply (1) and (2)2n1×3n2=n2n1×n3n23n1=n3n1

If the refractive index of second medium with the respect to first medium is $_{2} n_{1}$ and that of third medium with respect to second medium is $_{3} n_{2}$ , then $_{3} n_{1}$ will be?

$_{2} n_{1} = \frac{n_{2}}{n_{1}}$ ...(1)

$_{3} n_{2} = \frac{n_{3}}{n_{2}}$ ...(2)

multiply (1) and (2)

$_{2} n_{1} \times_{3} n_{2} = \frac{n_{2}}{n_{1}} \times \frac{n_{3}}{n_{2}}$

$_{3} n_{1} = \frac{n_{3}}{n_{1}}$