If the refractive index of the crown glass for red, yellow and violet colours are $1.514, 1.517 and 1.531$ respectively then, the dispersive power of the crown glass will be :

0.022

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0.045

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0.011

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0.033

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Solution

The correct option is D $0.033$
Given,
$n_{R} = 1.514$
$n_{Y} = 1.517$
$n_{V} = 1.531$

We know that,
Dispersive power $(ω) = \frac{n_{V} - n_{R}}{n_{Y} - 1}$
So, $ω = \frac{1.531 - 1.514}{1.517 - 1}$
$\Rightarrow ω = \frac{0.017}{0.517}$
$\Rightarrow ω \approx 0.033$

Hence, option $(d)$ is the correct answer.

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If the refractive index of the crown glass for red, yellow and violet colours are 1.514,1.517 and 1.531 respectively then, the dispersive power of the crown glass will be :

The correct option is D 0.033Given, nR=1.514 nY=1.517 nV=1.531 We know that, Dispersive power (ω)=nV−nRnY−1 So, ω=1.531−1.5141.517−1 ⇒ω=0.0170.517 ⇒ω≈0.033 Hence, option (d) is the correct answer.

If the refractive index of the crown glass for red, yellow and violet colours are $1.514, 1.517 and 1.531$ respectively then, the dispersive power of the crown glass will be :