If the relation R:A→B where A={1,2,3,4} and B={1,3,5} is defined by R={(x,y):x<y,x∈A,y∈B}, then ROR−1 is
Since R = {(1,3)(1,5)(2,3)(2,5)(3,5)(4,5)}
And R−1 = {(3,1)(5,1)(3,2)(5,2)(5,3)(5,4)}
Thus, ROR−1 = {(3,5)(5,5)(3,3)(5,3)}