If the relative rates of abstraction of 2 and 1 H atoms 3.8 and 1.0, respectively, then the percentage ratios of the products 1-chloro-, 2- chloro-, and 3-chloro- are obtained in the photochlorination of n-hexane would be :

17%, 41.5%, 41.5% respectively

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17%, 17%, 66% respectively

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30%, 40%, 30% respectively

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15%, 15%, 70% respectively

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Solution

The correct option is C 17%, 41.5%, 41.5% respectively
Compound Relative
amount $%$
R.E.F image $3 H$ on $C .1$ and
$3 H$ on $C .6$
$6 \times 1 = 6.0$
$\frac{6 \times 100}{34.4} = 17.44$

ii. R.E.F image $2 H$ on $C .2$ and
$2 H$ on $C .5$
$4 \times 3.8 = 14.2$ $\frac{14.2 \times 100}{34.4} = 41.27$
iii. R.E.F image $2 H$ on $C .3$ and
$2 H$ on $C .4$
$4 \times 3.8 = 14.2$
______
Total $= 34.2$ $\frac{14.2 \times 100}{34.4} = 41.27$

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Compound	Relative amount	$%$
R.E.F image	$3 H$ on $C .1$ and $3 H$ on $C .6$ $6 \times 1 = 6.0$	$\frac{6 \times 100}{34.4} = 17.44$

ii. R.E.F image	$2 H$ on $C .2$ and $2 H$ on $C .5$ $4 \times 3.8 = 14.2$	$\frac{14.2 \times 100}{34.4} = 41.27$
iii. R.E.F image	$2 H$ on $C .3$ and $2 H$ on $C .4$ $4 \times 3.8 = 14.2$ ______ Total $= 34.2$	$\frac{14.2 \times 100}{34.4} = 41.27$