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Question

If the remainder obtained on dividing the polynomial 2x3 − 9x2 + 8x + 15 by (x − 1) is R1 and the remainder obtained on dividing the polynomial x2 − 10x + 50 by (x − 5) is R2, then what is the value of R1 − R2?


A

-9

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B

-5

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C

5

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D

9

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Solution

The correct option is A

-9


According to the remainder theorem, when a polynomial p(x) is divided by a linear polynomial (x − a), the remainder obtained is p(a).

Let f(x) = 2x3 − 9x2 + 8x + 15 and g (x) = x2 − 10x + 50

Now, the zero of (x − 1) is 1.

It is given that the remainder obtained on dividing the polynomial f(x) by (x − 1) is R1.

∴ R1 = f(1)

⇒ R1 = 2(1)3 − 9(1)2 + 8(1) + 15 = 2 − 9 + 8 + 15 = 25 − 9 = 16

The zero of (x − 5) is 5.

It is given that the remainder obtained on dividing the polynomial g(x) by (x − 5) is R2.

∴ R2 = g(5)

⇒ R2 = (5)2 − 10(5) + 50 = 25 − 50 + 50 = 25

∴ R1 − R2 = 16 − 25 = −9

Thus, the value of R1 − R2 is −9.


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