If the repayment of debt is in a number of installments, the equation would be __________________.

{C I}_{o} = \sum_{t = 1}^{n} \frac{C o I_{t}}{{(1 + k_{d})}^{t}} + \frac{C o P_{n}}{{(1 + k_{d})}^{n}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C I}_{o} = \sum_{t = 1}^{n} \frac{C o I_{t} + C o P_{t}}{{(1 + k_{d})}^{t}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

k_{i} = \frac{1}{S_{v}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

k_{d} = \frac{1}{S_{v}} (1 - t)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B ${C I}_{o} = \sum_{t = 1}^{n} \frac{C o I_{t} + C o P_{t}}{{(1 + k_{d})}^{t}}$
finance

Suggest Corrections

Similar questions

S_{n} = \sum_{r = 1}^{n} T_{r} = n (n + 1) (n + 2) (n + 3)

\sum_{r = 1}^{n} \frac{1}{T}

\sum_{t = 1}^{n} t_{r} = \frac{1}{6} n (n + 1) (n + 2) \forall n \geq 1.

{lim}_{n \to \infty} \sum_{r = 1}^{n} \frac{1}{t_{r}}

S_{n} = n \sum r = 1 r - 1 \sum t = 0 (\frac{1}{6^{n}}^{n} C_{r}^{r} C_{t} 4^{t}),

l,

l = \infty \sum n = 1 (1 - S_{n})

x^{n} - 1 = 0, n > 1, n \in N,

1, a_{1}, a_{2}, \dots, a_{n - 1},

C_{m + 1}^{n + 1} : C_{m}^{n + 1} : C_{m - 1}^{n + 1} = 5 : 5 : 3

Join BYJU'S Learning Program