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Byju's Answer
Standard XII
Physics
Power in an AC Circuit
If the resist...
Question
If the resistance of conductor is
R
, then total heat dissipated across resistance
R
is:
A
i
2
0
R
t
0
2
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B
i
2
0
R
t
0
4
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C
i
2
0
R
t
0
3
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D
i
2
0
R
t
0
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Solution
The correct option is
C
i
2
0
R
t
0
3
Equation =
i
i
0
+
t
t
0
=
1
Heat dissipated
=
∫
c
2
R
d
t
=
∫
t
o
0
(
−
t
t
0
)
2
i
2
0
R
a
t
On solving integration we get ,
Heat dissipated
=
i
2
0
R
t
0
3
Joules
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