The correct option is C 5√3/2 A
Formula used:
I=I0sinω t,
I0=√2Irms
Given, Frequency, v=50 Hz
Irms=5 A,
t=1300s
As we know, I0√2=Irms
Where, I0=peak current
I0=√2Irms=√2×5 A
Since,
I=I0sinω t
I=5√2sin100π×1300
=5√2sinπ3
=5√2×√32
I=5√32 A
Final Answer: 5√32 A